(5x+4)(2x^2-5x-3)=0

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Solution for (5x+4)(2x^2-5x-3)=0 equation: 


Simplifying
(5x + 4)(2x2 + -5x + -3) = 0

Reorder the terms:
(4 + 5x)(2x2 + -5x + -3) = 0

Reorder the terms:
(4 + 5x)(-3 + -5x + 2x2) = 0

Multiply (4 + 5x) * (-3 + -5x + 2x2)
(4(-3 + -5x + 2x2) + 5x * (-3 + -5x + 2x2)) = 0
((-3 * 4 + -5x * 4 + 2x2 * 4) + 5x * (-3 + -5x + 2x2)) = 0
((-12 + -20x + 8x2) + 5x * (-3 + -5x + 2x2)) = 0
(-12 + -20x + 8x2 + (-3 * 5x + -5x * 5x + 2x2 * 5x)) = 0
(-12 + -20x + 8x2 + (-15x + -25x2 + 10x3)) = 0

Reorder the terms:
(-12 + -20x + -15x + 8x2 + -25x2 + 10x3) = 0

Combine like terms: -20x + -15x = -35x
(-12 + -35x + 8x2 + -25x2 + 10x3) = 0

Combine like terms: 8x2 + -25x2 = -17x2
(-12 + -35x + -17x2 + 10x3) = 0

Solving
-12 + -35x + -17x2 + 10x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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